ASVAB Math Knowledge Practice Test 240614

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4c - 8c = -5c - z + 1 for c in terms of z.

1\(\frac{1}{3}\)z - 1
-2\(\frac{2}{3}\)z - 2
-z + \(\frac{7}{10}\)
7z + 1