When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 2c = 4c + 2z + 1 for c in terms of z.
| -\(\frac{9}{14}\)z - \(\frac{4}{7}\) | |
| z + \(\frac{1}{5}\) | |
| -\(\frac{4}{13}\)z - \(\frac{7}{13}\) | |
| -\(\frac{2}{9}\)z - \(\frac{2}{3}\) |