When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -2c + 2c = 4c + 3z + 5 for c in terms of z.
| -\(\frac{1}{6}\)z - \(\frac{5}{6}\) | |
| 2\(\frac{2}{5}\)z - 1\(\frac{3}{5}\) | |
| \(\frac{1}{7}\)z - 1\(\frac{2}{7}\) | |
| -1\(\frac{1}{5}\)z - \(\frac{2}{5}\) |