ASVAB Math Knowledge Practice Test 241914

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4a - 3a = 5a - 5z + 2 for a in terms of z.

-\(\frac{1}{2}\)z - \(\frac{1}{2}\)
12z + 6
-2\(\frac{1}{2}\)z - 1
2z - 2