| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
Simplify (4a)(8ab) + (9a2)(6b).
| -22ab2 | |
| 86a2b | |
| 22a2b | |
| -22a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(4a)(8ab) + (9a2)(6b)
(4 x 8)(a x a x b) + (9 x 6)(a2 x b)
(32)(a1+1 x b) + (54)(a2b)
32a2b + 54a2b
86a2b
Which of the following is not required to define the slope-intercept equation for a line?
slope |
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x-intercept |
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y-intercept |
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\({\Delta y \over \Delta x}\) |
A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.
Breaking apart a quadratic expression into a pair of binomials is called:
factoring |
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squaring |
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deconstructing |
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normalizing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
This diagram represents two parallel lines with a transversal. If d° = 164, what is the value of c°?
| 163 | |
| 31 | |
| 16 | |
| 33 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with d° = 164, the value of c° is 16.
The endpoints of this line segment are at (-2, 1) and (2, 3). What is the slope of this line?
| -1 | |
| \(\frac{1}{2}\) | |
| -3 | |
| 3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, 3) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(3.0) - (1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)