ASVAB Math Knowledge Practice Test 242625 Results

Your Results Global Average
Questions 5 5
Correct 0 3.00
Score 0% 60%

Review

1

Simplify (4a)(8ab) + (9a2)(6b).

65% Answer Correctly
-22ab2
86a2b
22a2b
-22a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(4a)(8ab) + (9a2)(6b)
(4 x 8)(a x a x b) + (9 x 6)(a2 x b)
(32)(a1+1 x b) + (54)(a2b)
32a2b + 54a2b
86a2b


2

Which of the following is not required to define the slope-intercept equation for a line?

41% Answer Correctly

slope

x-intercept

y-intercept

\({\Delta y \over \Delta x}\)


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


3

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

factoring

squaring

deconstructing

normalizing


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.


4

This diagram represents two parallel lines with a transversal. If d° = 164, what is the value of c°?

73% Answer Correctly
163
31
16
33

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with d° = 164, the value of c° is 16.


5

The endpoints of this line segment are at (-2, 1) and (2, 3). What is the slope of this line?

46% Answer Correctly
-1
\(\frac{1}{2}\)
-3
3

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, 3) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(3.0) - (1.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)