| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
If the area of this square is 1, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 4\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 9\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)
The dimensions of this cylinder are height (h) = 5 and radius (r) = 3. What is the surface area?
| 210π | |
| 60π | |
| 16π | |
| 48π |
The surface area of a cylinder is 2πr2 + 2πrh:
sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 5)
sa = 2π(9) + 2π(15)
sa = (2 x 9)π + (2 x 15)π
sa = 18π + 30π
sa = 48π
The dimensions of this cube are height (h) = 9, length (l) = 5, and width (w) = 7. What is the surface area?
| 286 | |
| 178 | |
| 280 | |
| 78 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 5 x 7) + (2 x 7 x 9) + (2 x 5 x 9)
sa = (70) + (126) + (90)
sa = 286
If side x = 5cm, side y = 10cm, and side z = 5cm what is the perimeter of this triangle?
| 36cm | |
| 31cm | |
| 20cm | |
| 37cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 5cm + 10cm + 5cm = 20cm
Which types of triangles will always have at least two sides of equal length?
equilateral and right |
|
equilateral, isosceles and right |
|
isosceles and right |
|
equilateral and isosceles |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.