ASVAB Math Knowledge Practice Test 243010

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 7c + 2c = c + 3z + 8 for c in terms of z.

-\(\frac{8}{9}\)z + \(\frac{2}{3}\)
\(\frac{1}{6}\)z + 1\(\frac{1}{3}\)
2z - 2
4z - 4\(\frac{1}{2}\)