When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8c + 3c = -7c - 4x - 2 for c in terms of x.
| -1\(\frac{1}{6}\)x - 1\(\frac{1}{2}\) | |
| \(\frac{7}{9}\)x + \(\frac{1}{3}\) | |
| -\(\frac{1}{6}\)x + \(\frac{1}{4}\) | |
| -\(\frac{7}{15}\)x - \(\frac{2}{15}\) |