| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
If a = c = 5, b = d = 2, and the blue angle = 55°, what is the area of this parallelogram?
| 30 | |
| 10 | |
| 40 | |
| 72 |
The area of a parallelogram is equal to its length x width:
a = l x w
a = a x b
a = 5 x 2
a = 10
Simplify (7a)(3ab) + (9a2)(2b).
| 110ab2 | |
| 39a2b | |
| 110a2b | |
| -3ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(3ab) + (9a2)(2b)
(7 x 3)(a x a x b) + (9 x 2)(a2 x b)
(21)(a1+1 x b) + (18)(a2b)
21a2b + 18a2b
39a2b
If angle a = 43° and angle b = 41° what is the length of angle d?
| 148° | |
| 146° | |
| 156° | |
| 137° |
An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:
d° = b° + c°
To find angle c, remember that the sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 43° - 41° = 96°
So, d° = 41° + 96° = 137°
A shortcut to get this answer is to remember that angles around a line add up to 180°:
a° + d° = 180°
d° = 180° - a°
d° = 180° - 43° = 137°
Solve for z:
z2 - 4z - 5 = 0
| -1 or 5 | |
| 1 or -6 | |
| 1 or -4 | |
| 9 or 2 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
z2 - 4z - 5 = 0
(z + 1)(z - 5) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z + 1) or (z - 5) must equal zero:
If (z + 1) = 0, z must equal -1
If (z - 5) = 0, z must equal 5
So the solution is that z = -1 or 5
If BD = 9 and AD = 11, AB = ?
| 15 | |
| 4 | |
| 20 | |
| 2 |
The entire length of this line is represented by AD which is AB + BD:
AD = AB + BD
Solving for AB:AB = AD - BD