When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c + 3c = -8c - 2y - 6 for c in terms of y.
| 7y + 1 | |
| -\(\frac{5}{12}\)y - \(\frac{1}{2}\) | |
| 8y - 5 | |
| -\(\frac{3}{16}\)y + \(\frac{1}{4}\) |