ASVAB Math Knowledge Practice Test 24874 Results

Your Results Global Average
Questions 5 5
Correct 0 2.54
Score 0% 51%

Review

1

Solve -3a - 6a = a - 4z + 6 for a in terms of z.

34% Answer Correctly
2z - 1
\(\frac{3}{5}\)z + 1\(\frac{1}{5}\)
-\(\frac{1}{2}\)z - 1\(\frac{1}{2}\)
-1\(\frac{1}{3}\)z + \(\frac{5}{6}\)

Solution

To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.

-3a - 6z = a - 4z + 6
-3a = a - 4z + 6 + 6z
-3a - a = -4z + 6 + 6z
-4a = 2z + 6
a = \( \frac{2z + 6}{-4} \)
a = \( \frac{2z}{-4} \) + \( \frac{6}{-4} \)
a = -\(\frac{1}{2}\)z - 1\(\frac{1}{2}\)


2

Which of the following is not required to define the slope-intercept equation for a line?

42% Answer Correctly

slope

y-intercept

x-intercept

\({\Delta y \over \Delta x}\)


Solution

A line on the coordinate grid can be defined by a slope-intercept equation: y = mx + b. For a given value of x, the value of y can be determined given the slope (m) and y-intercept (b) of the line. The slope of a line is change in y over change in x, \({\Delta y \over \Delta x}\), and the y-intercept is the y-coordinate where the line crosses the vertical y-axis.


3

Simplify (6a)(4ab) + (2a2)(5b).

65% Answer Correctly
34a2b
34ab2
70a2b
14a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(4ab) + (2a2)(5b)
(6 x 4)(a x a x b) + (2 x 5)(a2 x b)
(24)(a1+1 x b) + (10)(a2b)
24a2b + 10a2b
34a2b


4

Factor y2 + 16y + 63

54% Answer Correctly
(y - 7)(y + 9)
(y - 7)(y - 9)
(y + 7)(y + 9)
(y + 7)(y - 9)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 63 as well and sum (Inside, Outside) to equal 16. For this problem, those two numbers are 7 and 9. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 16y + 63
y2 + (7 + 9)y + (7 x 9)
(y + 7)(y + 9)


5

If the base of this triangle is 3 and the height is 4, what is the area?

58% Answer Correctly
36
6
91
60

Solution

The area of a triangle is equal to ½ base x height:

a = ½bh
a = ½ x 3 x 4 = \( \frac{12}{2} \) = 6