ASVAB Math Knowledge Practice Test 24918

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c + 6c = c - 9y + 2 for c in terms of y.

-7\(\frac{1}{2}\)y + 1
y + 1\(\frac{3}{5}\)
5y - \(\frac{1}{2}\)
\(\frac{3}{10}\)y + \(\frac{7}{10}\)