When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c - 3c = -5c - 4z + 6 for c in terms of z.
| z - 1\(\frac{1}{5}\) | |
| \(\frac{1}{3}\)z + \(\frac{5}{9}\) | |
| -\(\frac{5}{9}\)z - \(\frac{7}{9}\) | |
| -\(\frac{1}{2}\)z + 3 |