ASVAB Math Knowledge Practice Test 252256

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6b + 6b = -2b - 8z + 3 for b in terms of z.

-z - \(\frac{3}{8}\)
3\(\frac{1}{2}\)z - \(\frac{3}{4}\)
2\(\frac{3}{4}\)z + 2\(\frac{1}{4}\)
-1\(\frac{1}{8}\)z + \(\frac{1}{4}\)