ASVAB Math Knowledge Practice Test 254119 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

If a = 1, b = 6, c = 8, and d = 1, what is the perimeter of this quadrilateral?

88% Answer Correctly
16
26
11
22

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 1 + 6 + 8 + 1
p = 16


2

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

quadrilateral

triangle

trapezoid

rhombus


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


3

Which of the following statements about a parallelogram is not true?

49% Answer Correctly

the area of a parallelogram is base x height

opposite sides and adjacent angles are equal

a parallelogram is a quadrilateral

the perimeter of a parallelogram is the sum of the lengths of all sides


Solution

A parallelogram is a quadrilateral with two sets of parallel sides. Opposite sides (a = c, b = d) and angles (red = red, blue = blue) are equal. The area of a parallelogram is base x height and the perimeter is the sum of the lengths of all sides (a + b + c + d).


4

What is 9a5 - 2a5?

73% Answer Correctly
7a5
7a10
11a10
18a10

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

9a5 - 2a5 = 7a5


5

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
9\( \sqrt{2} \)
\( \sqrt{2} \)
6\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)