| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.34 |
| Score | 0% | 67% |
This diagram represents two parallel lines with a transversal. If y° = 168, what is the value of c°?
| 26 | |
| 12 | |
| 30 | |
| 18 |
For parallel lines with a transversal, the following relationships apply:
Applying these relationships starting with y° = 168, the value of c° is 12.
Solve for y:
9y - 1 < -3 + 8y
| y < -\(\frac{1}{3}\) | |
| y < -2 | |
| y < 1\(\frac{2}{3}\) | |
| y < \(\frac{2}{3}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
9y - 1 < -3 + 8y
9y < -3 + 8y + 1
9y - 8y < -3 + 1
y < -2
The dimensions of this cube are height (h) = 7, length (l) = 9, and width (w) = 8. What is the volume?
| 70 | |
| 72 | |
| 504 | |
| 162 |
The volume of a cube is height x length x width:
v = h x l x w
v = 7 x 9 x 8
v = 504
What is 6a4 - 8a4?
| -2 | |
| 14 | |
| -2a8 | |
| -2a4 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
6a4 - 8a4 = -2a4
The dimensions of this trapezoid are a = 5, b = 2, c = 7, d = 5, and h = 3. What is the area?
| 10\(\frac{1}{2}\) | |
| 15 | |
| 24 | |
| 13\(\frac{1}{2}\) |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(2 + 5)(3)
a = ½(7)(3)
a = ½(21) = \( \frac{21}{2} \)
a = 10\(\frac{1}{2}\)