ASVAB Math Knowledge Practice Test 254642 Results

Your Results Global Average
Questions 5 5
Correct 0 3.34
Score 0% 67%

Review

1

This diagram represents two parallel lines with a transversal. If y° = 168, what is the value of c°?

73% Answer Correctly
26
12
30
18

Solution

For parallel lines with a transversal, the following relationships apply:

  • angles in the same position on different parallel lines equal each other (a° = w°, b° = x°, c° = z°, d° = y°)
  • alternate interior angles are equal (a° = z°, b° = y°, c° = w°, d° = x°)
  • all acute angles (a° = c° = w° = z°) and all obtuse angles (b° = d° = x° = y°) equal each other
  • same-side interior angles are supplementary and add up to 180° (e.g. a° + d° = 180°, d° + c° = 180°)

Applying these relationships starting with y° = 168, the value of c° is 12.


2

Solve for y:
9y - 1 < -3 + 8y

55% Answer Correctly
y < -\(\frac{1}{3}\)
y < -2
y < 1\(\frac{2}{3}\)
y < \(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

9y - 1 < -3 + 8y
9y < -3 + 8y + 1
9y - 8y < -3 + 1
y < -2


3

The dimensions of this cube are height (h) = 7, length (l) = 9, and width (w) = 8. What is the volume?

82% Answer Correctly
70
72
504
162

Solution

The volume of a cube is height x length x width:

v = h x l x w
v = 7 x 9 x 8
v = 504


4

What is 6a4 - 8a4?

73% Answer Correctly
-2
14
-2a8
-2a4

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a4 - 8a4 = -2a4


5

The dimensions of this trapezoid are a = 5, b = 2, c = 7, d = 5, and h = 3. What is the area?

50% Answer Correctly
10\(\frac{1}{2}\)
15
24
13\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(2 + 5)(3)
a = ½(7)(3)
a = ½(21) = \( \frac{21}{2} \)
a = 10\(\frac{1}{2}\)