| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
The endpoints of this line segment are at (-2, -2) and (2, -4). What is the slope of this line?
| -2\(\frac{1}{2}\) | |
| 1 | |
| -\(\frac{1}{2}\) | |
| -1\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, -4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-4.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)Order the following types of angle from least number of degrees to most number of degrees.
right, obtuse, acute |
|
right, acute, obtuse |
|
acute, obtuse, right |
|
acute, right, obtuse |
An acute angle measures less than 90°, a right angle measures 90°, and an obtuse angle measures more than 90°.
If the base of this triangle is 4 and the height is 8, what is the area?
| 21 | |
| 65 | |
| 97\(\frac{1}{2}\) | |
| 16 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 4 x 8 = \( \frac{32}{2} \) = 16
Solve for c:
-6c + 4 < 9 + c
| c < -\(\frac{5}{7}\) | |
| c < 6 | |
| c < -\(\frac{1}{4}\) | |
| c < \(\frac{3}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-6c + 4 < 9 + c
-6c < 9 + c - 4
-6c - c < 9 - 4
-7c < 5
c < \( \frac{5}{-7} \)
c < -\(\frac{5}{7}\)
If side x = 11cm, side y = 14cm, and side z = 5cm what is the perimeter of this triangle?
| 26cm | |
| 30cm | |
| 35cm | |
| 29cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 11cm + 14cm + 5cm = 30cm