| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.39 |
| Score | 0% | 68% |
Breaking apart a quadratic expression into a pair of binomials is called:
normalizing |
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squaring |
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factoring |
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deconstructing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
Simplify (3a)(4ab) - (6a2)(6b).
| 48a2b | |
| 84ab2 | |
| 24ab2 | |
| -24a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(3a)(4ab) - (6a2)(6b)
(3 x 4)(a x a x b) - (6 x 6)(a2 x b)
(12)(a1+1 x b) - (36)(a2b)
12a2b - 36a2b
-24a2b
Which of the following is not a part of PEMDAS, the acronym for math order of operations?
pairs |
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addition |
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exponents |
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division |
When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Simplify (6a)(2ab) + (5a2)(3b).
| 27a2b | |
| 3ab2 | |
| -3a2b | |
| 3a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(6a)(2ab) + (5a2)(3b)
(6 x 2)(a x a x b) + (5 x 3)(a2 x b)
(12)(a1+1 x b) + (15)(a2b)
12a2b + 15a2b
27a2b
For this diagram, the Pythagorean theorem states that b2 = ?
c2 - a2 |
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a2 - c2 |
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c2 + a2 |
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c - a |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)