ASVAB Math Knowledge Practice Test 255677 Results

Your Results Global Average
Questions 5 5
Correct 0 3.23
Score 0% 65%

Review

1

If side x = 5cm, side y = 15cm, and side z = 13cm what is the perimeter of this triangle?

84% Answer Correctly
40cm
19cm
33cm
34cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 5cm + 15cm + 13cm = 33cm


2

The endpoints of this line segment are at (-2, 0) and (2, -6). What is the slope-intercept equation for this line?

41% Answer Correctly
y = x + 2
y = -1\(\frac{1}{2}\)x + 2
y = -2\(\frac{1}{2}\)x - 2
y = -1\(\frac{1}{2}\)x - 3

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -3. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 0) and (2, -6) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (0.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)
m = -1\(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = -1\(\frac{1}{2}\)x - 3


3

If BD = 26 and AD = 29, AB = ?

75% Answer Correctly
20
3
17
1

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 29 - 26
AB = 3


4

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

obtuse, acute

vertical, supplementary

acute, obtuse

supplementary, vertical


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


5

The dimensions of this cylinder are height (h) = 4 and radius (r) = 1. What is the volume?

62% Answer Correctly
512π
288π
180π

Solution

The volume of a cylinder is πr2h:

v = πr2h
v = π(12 x 4)
v = 4π