ASVAB Math Knowledge Practice Test 255699 Results

Your Results Global Average
Questions 5 5
Correct 0 3.30
Score 0% 66%

Review

1

What is 4a2 - 6a2?

73% Answer Correctly
-2a2
-2a4
10
24a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

4a2 - 6a2 = -2a2


2

The dimensions of this trapezoid are a = 6, b = 5, c = 9, d = 4, and h = 4. What is the area?

51% Answer Correctly
27\(\frac{1}{2}\)
22\(\frac{1}{2}\)
18
22

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(5 + 4)(4)
a = ½(9)(4)
a = ½(36) = \( \frac{36}{2} \)
a = 18


3

What is 3a2 + 4a2?

75% Answer Correctly
7a2
12a2
7
a24

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

3a2 + 4a2 = 7a2


4

Solve for z:
z + 8 = \( \frac{z}{-1} \)

46% Answer Correctly
-4
1\(\frac{7}{41}\)
-1\(\frac{1}{71}\)
-1\(\frac{1}{17}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

z + 8 = \( \frac{z}{-1} \)
-1 x (z + 8) = z
(-1 x z) + (-1 x 8) = z
-z - 8 = z
-z - 8 - z = 0
-z - z = 8
-2z = 8
z = \( \frac{8}{-2} \)
z = -4


5

If side x = 11cm, side y = 12cm, and side z = 7cm what is the perimeter of this triangle?

84% Answer Correctly
24cm
30cm
28cm
32cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 11cm + 12cm + 7cm = 30cm