When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2c + 6c = -9c + 8z + 5 for c in terms of z.
| \(\frac{2}{11}\)z + \(\frac{5}{11}\) | |
| 4\(\frac{1}{3}\)z + 2\(\frac{1}{3}\) | |
| \(\frac{2}{3}\)z + 2 | |
| -2\(\frac{1}{4}\)z + \(\frac{1}{2}\) |