| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.70 |
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A(n) __________ is to a parallelogram as a square is to a rectangle.
trapezoid |
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rhombus |
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quadrilateral |
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triangle |
A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.
The dimensions of this cube are height (h) = 2, length (l) = 8, and width (w) = 8. What is the surface area?
| 78 | |
| 100 | |
| 192 | |
| 82 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 8 x 8) + (2 x 8 x 2) + (2 x 8 x 2)
sa = (128) + (32) + (32)
sa = 192
The endpoints of this line segment are at (-2, 4) and (2, -2). What is the slope-intercept equation for this line?
| y = x - 4 | |
| y = -1\(\frac{1}{2}\)x + 1 | |
| y = -2x - 2 | |
| y = -1\(\frac{1}{2}\)x + 3 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 4) and (2, -2) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (4.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)Plugging these values into the slope-intercept equation:
y = -1\(\frac{1}{2}\)x + 1
If the area of this square is 1, what is the length of one of the diagonals?
| 2\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)
Solve for b:
b2 - 81 = 0
| 9 or -9 | |
| 3 or -5 | |
| 4 or 3 | |
| 8 or 3 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
b2 - 81 = 0
(b - 9)(b + 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 9) or (b + 9) must equal zero:
If (b - 9) = 0, b must equal 9
If (b + 9) = 0, b must equal -9
So the solution is that b = 9 or -9