ASVAB Math Knowledge Practice Test 256585 Results

Your Results Global Average
Questions 5 5
Correct 0 2.70
Score 0% 54%

Review

1

A(n) __________ is to a parallelogram as a square is to a rectangle.

52% Answer Correctly

trapezoid

rhombus

quadrilateral

triangle


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


2

The dimensions of this cube are height (h) = 2, length (l) = 8, and width (w) = 8. What is the surface area?

51% Answer Correctly
78
100
192
82

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 8 x 8) + (2 x 8 x 2) + (2 x 8 x 2)
sa = (128) + (32) + (32)
sa = 192


3

The endpoints of this line segment are at (-2, 4) and (2, -2). What is the slope-intercept equation for this line?

41% Answer Correctly
y = x - 4
y = -1\(\frac{1}{2}\)x + 1
y = -2x - 2
y = -1\(\frac{1}{2}\)x + 3

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is 1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 4) and (2, -2) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-2.0) - (4.0)}{(2) - (-2)} \) = \( \frac{-6}{4} \)
m = -1\(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = -1\(\frac{1}{2}\)x + 1


4

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
2\( \sqrt{2} \)
\( \sqrt{2} \)
5\( \sqrt{2} \)
8\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)


5

Solve for b:
b2 - 81 = 0

58% Answer Correctly
9 or -9
3 or -5
4 or 3
8 or 3

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

b2 - 81 = 0
(b - 9)(b + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 9) or (b + 9) must equal zero:

If (b - 9) = 0, b must equal 9
If (b + 9) = 0, b must equal -9

So the solution is that b = 9 or -9