When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 2c = -9c + 5x - 4 for c in terms of x.
| \(\frac{1}{12}\)x + \(\frac{1}{6}\) | |
| \(\frac{2}{5}\)x + \(\frac{2}{5}\) | |
| \(\frac{7}{13}\)x - \(\frac{4}{13}\) | |
| \(\frac{1}{4}\)x + \(\frac{1}{3}\) |