When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c - 4c = 2c + 8z - 5 for c in terms of z.
| 4z - 1\(\frac{2}{3}\) | |
| -6z + 8 | |
| -5z - 5 | |
| z - \(\frac{4}{5}\) |