ASVAB Math Knowledge Practice Test 25938

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3c + 7c = -5c - z + 2 for c in terms of z.

-z + \(\frac{1}{4}\)
5\(\frac{1}{3}\)z - \(\frac{2}{3}\)
\(\frac{1}{2}\)z - 1\(\frac{1}{8}\)
\(\frac{1}{13}\)z + \(\frac{8}{13}\)