When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 9c = -4c + 5z + 6 for c in terms of z.
| -\(\frac{4}{9}\)z + \(\frac{2}{3}\) | |
| -\(\frac{1}{12}\)z - \(\frac{1}{4}\) | |
| -2\(\frac{1}{3}\)z - \(\frac{1}{3}\) | |
| -z - 1 |