ASVAB Math Knowledge Practice Test 260080

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -4a - 9a = 8a + 5z - 5 for a in terms of z.

-\(\frac{1}{2}\)z + \(\frac{1}{14}\)
-1\(\frac{1}{6}\)z + \(\frac{5}{12}\)
\(\frac{1}{6}\)z - \(\frac{1}{3}\)
\(\frac{1}{8}\)z + \(\frac{3}{8}\)