| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
What is the area of a circle with a radius of 5?
| 5π | |
| 4π | |
| 25π | |
| 81π |
The formula for area is πr2:
a = πr2
a = π(52)
a = 25π
If angle a = 36° and angle b = 58° what is the length of angle c?
| 107° | |
| 106° | |
| 86° | |
| 89° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 36° - 58° = 86°
If the area of this square is 9, what is the length of one of the diagonals?
| 5\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| 6\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)
Simplify (9a)(3ab) - (7a2)(8b).
| 29ab2 | |
| 83a2b | |
| -29a2b | |
| 180a2b |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(9a)(3ab) - (7a2)(8b)
(9 x 3)(a x a x b) - (7 x 8)(a2 x b)
(27)(a1+1 x b) - (56)(a2b)
27a2b - 56a2b
-29a2b
The endpoints of this line segment are at (-2, -3) and (2, -1). What is the slope-intercept equation for this line?
| y = \(\frac{1}{2}\)x - 2 | |
| y = 2\(\frac{1}{2}\)x - 2 | |
| y = -3x - 3 | |
| y = 2\(\frac{1}{2}\)x - 4 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, -1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)Plugging these values into the slope-intercept equation:
y = \(\frac{1}{2}\)x - 2