ASVAB Math Knowledge Practice Test 260284 Results

Your Results Global Average
Questions 5 5
Correct 0 3.11
Score 0% 62%

Review

1

What is the area of a circle with a radius of 5?

69% Answer Correctly
25π
81π

Solution

The formula for area is πr2:

a = πr2
a = π(52)
a = 25π


2

If angle a = 36° and angle b = 58° what is the length of angle c?

71% Answer Correctly
107°
106°
86°
89°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 36° - 58° = 86°


3

If the area of this square is 9, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
8\( \sqrt{2} \)
6\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)


4

Simplify (9a)(3ab) - (7a2)(8b).

62% Answer Correctly
29ab2
83a2b
-29a2b
180a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(9a)(3ab) - (7a2)(8b)
(9 x 3)(a x a x b) - (7 x 8)(a2 x b)
(27)(a1+1 x b) - (56)(a2b)
27a2b - 56a2b
-29a2b


5

The endpoints of this line segment are at (-2, -3) and (2, -1). What is the slope-intercept equation for this line?

41% Answer Correctly
y = \(\frac{1}{2}\)x - 2
y = 2\(\frac{1}{2}\)x - 2
y = -3x - 3
y = 2\(\frac{1}{2}\)x - 4

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, -1) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-1.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{2}{4} \)
m = \(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = \(\frac{1}{2}\)x - 2