ASVAB Math Knowledge Practice Test 260566 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

Solve for y:
-3y + 2 < \( \frac{y}{2} \)

44% Answer Correctly
y < -\(\frac{8}{9}\)
y < \(\frac{4}{15}\)
y < 3\(\frac{1}{2}\)
y < \(\frac{4}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-3y + 2 < \( \frac{y}{2} \)
2 x (-3y + 2) < y
(2 x -3y) + (2 x 2) < y
-6y + 4 < y
-6y + 4 - y < 0
-6y - y < -4
-7y < -4
y < \( \frac{-4}{-7} \)
y < \(\frac{4}{7}\)


2

Simplify (6a)(8ab) + (7a2)(4b).

66% Answer Correctly
-20ab2
76ab2
20a2b
76a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(6a)(8ab) + (7a2)(4b)
(6 x 8)(a x a x b) + (7 x 4)(a2 x b)
(48)(a1+1 x b) + (28)(a2b)
48a2b + 28a2b
76a2b


3

A coordinate grid is composed of which of the following?

91% Answer Correctly

x-axis

all of these

y-axis

origin


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


4

Solve for c:
c2 - 2c - 15 = 5c + 3

48% Answer Correctly
6 or -4
-2 or 9
3 or -7
8 or -1

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

c2 - 2c - 15 = 5c + 3
c2 - 2c - 15 - 3 = 5c
c2 - 2c - 5c - 18 = 0
c2 - 7c - 18 = 0

Next, factor the quadratic equation:

c2 - 7c - 18 = 0
(c + 2)(c - 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (c + 2) or (c - 9) must equal zero:

If (c + 2) = 0, c must equal -2
If (c - 9) = 0, c must equal 9

So the solution is that c = -2 or 9


5

What is the circumference of a circle with a radius of 13?

71% Answer Correctly
18π
26π
36π

Solution

The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:

c = πd
c = π(2 * r)
c = π(2 * 13)
c = 26π