ASVAB Math Knowledge Practice Test 262200

Question 2 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 8a + 3a = 6a + 9z - 9 for a in terms of z.

\(\frac{1}{3}\)z + \(\frac{1}{3}\)
-1\(\frac{1}{12}\)z - \(\frac{1}{6}\)
3z - 4\(\frac{1}{2}\)
-12z + 3