When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8a + 9a = -4a + 2z - 3 for a in terms of z.
| 1\(\frac{2}{5}\)z - \(\frac{3}{5}\) | |
| \(\frac{4}{5}\)z - 1\(\frac{4}{5}\) | |
| z + 4 | |
| -\(\frac{7}{12}\)z - \(\frac{1}{4}\) |