ASVAB Math Knowledge Practice Test 262896

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6a + 5a = -4a - 4y + 4 for a in terms of y.

2\(\frac{1}{8}\)y - \(\frac{1}{4}\)
\(\frac{6}{11}\)y + \(\frac{6}{11}\)
\(\frac{1}{6}\)y + \(\frac{1}{6}\)
4\(\frac{1}{2}\)y - 2