ASVAB Math Knowledge Practice Test 263520

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve c + 9c = -c - 5z + 5 for c in terms of z.

-\(\frac{5}{9}\)z - \(\frac{1}{9}\)
-7z + 2\(\frac{1}{2}\)
-9z - 1
-\(\frac{4}{7}\)z - \(\frac{1}{7}\)