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Solve -8a + a = -7a + 7y + 3 for a in terms of y.
| 2\(\frac{3}{4}\)y + 1\(\frac{1}{2}\) | |
| 1\(\frac{2}{13}\)y - \(\frac{8}{13}\) | |
| -6y - 3 | |
| y - \(\frac{1}{10}\) |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
-8a + y = -7a + 7y + 3
-8a = -7a + 7y + 3 - y
-8a + 7a = 7y + 3 - y
-a = 6y + 3
a = \( \frac{6y + 3}{-1} \)
a = \( \frac{6y}{-1} \) + \( \frac{3}{-1} \)
a = -6y - 3
The endpoints of this line segment are at (-2, -1) and (2, 3). What is the slope of this line?
| 1 | |
| -3 | |
| -1\(\frac{1}{2}\) | |
| -2 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -1) and (2, 3) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(3.0) - (-1.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)What is the area of a circle with a diameter of 10?
| 9π | |
| 4π | |
| 2π | |
| 25π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{10}{2} \)
r = 5
a = πr2
a = π(52)
a = 25π
Simplify (7a)(4ab) - (3a2)(8b).
| -4ab2 | |
| 4a2b | |
| 121a2b | |
| 52ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(4ab) - (3a2)(8b)
(7 x 4)(a x a x b) - (3 x 8)(a2 x b)
(28)(a1+1 x b) - (24)(a2b)
28a2b - 24a2b
4a2b
Factor y2 - 15y + 56
| (y + 8)(y - 7) | |
| (y - 8)(y - 7) | |
| (y + 8)(y + 7) | |
| (y - 8)(y + 7) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 56 as well and sum (Inside, Outside) to equal -15. For this problem, those two numbers are -8 and -7. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 15y + 56
y2 + (-8 - 7)y + (-8 x -7)
(y - 8)(y - 7)