ASVAB Math Knowledge Practice Test 264832 Results

Your Results Global Average
Questions 5 5
Correct 0 2.73
Score 0% 55%

Review

1

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

supplementary, vertical

acute, obtuse

obtuse, acute

vertical, supplementary


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


2

Solve for c:
4c + 6 = -4 + 2c

59% Answer Correctly
-1
2\(\frac{2}{3}\)
-5
1\(\frac{1}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

4c + 6 = -4 + 2c
4c = -4 + 2c - 6
4c - 2c = -4 - 6
2c = -10
c = \( \frac{-10}{2} \)
c = -5


3

Solve for x:
2x - 9 > 2 - 3x

55% Answer Correctly
x > 2\(\frac{1}{5}\)
x > -\(\frac{2}{7}\)
x > -1\(\frac{1}{7}\)
x > -1\(\frac{2}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

2x - 9 > 2 - 3x
2x > 2 - 3x + 9
2x + 3x > 2 + 9
5x > 11
x > \( \frac{11}{5} \)
x > 2\(\frac{1}{5}\)


4

Solve for c:
-2c + 1 = \( \frac{c}{3} \)

46% Answer Correctly
\(\frac{5}{39}\)
\(\frac{3}{7}\)
-6
\(\frac{3}{13}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-2c + 1 = \( \frac{c}{3} \)
3 x (-2c + 1) = c
(3 x -2c) + (3 x 1) = c
-6c + 3 = c
-6c + 3 - c = 0
-6c - c = -3
-7c = -3
c = \( \frac{-3}{-7} \)
c = \(\frac{3}{7}\)


5

Factor y2 + 14y + 48

54% Answer Correctly
(y + 6)(y + 8)
(y - 6)(y - 8)
(y + 6)(y - 8)
(y - 6)(y + 8)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 48 as well and sum (Inside, Outside) to equal 14. For this problem, those two numbers are 6 and 8. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 + 14y + 48
y2 + (6 + 8)y + (6 x 8)
(y + 6)(y + 8)