When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 3c = 7c - 5y + 1 for c in terms of y.
| y - 1 | |
| -1\(\frac{1}{5}\)y - 1\(\frac{2}{5}\) | |
| 2\(\frac{1}{4}\)y - \(\frac{1}{4}\) | |
| 4y - \(\frac{1}{2}\) |