| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.53 |
| Score | 0% | 51% |
Solve 5a - 5a = -7a + 8x - 9 for a in terms of x.
| -\(\frac{2}{15}\)x + \(\frac{1}{3}\) | |
| -1\(\frac{4}{7}\)x - 1 | |
| 1\(\frac{1}{12}\)x - \(\frac{3}{4}\) | |
| -1\(\frac{1}{7}\)x + 1 |
To solve this equation, isolate the variable for which you are solving (a) on one side of the equation and put everything else on the other side.
5a - 5x = -7a + 8x - 9
5a = -7a + 8x - 9 + 5x
5a + 7a = 8x - 9 + 5x
12a = 13x - 9
a = \( \frac{13x - 9}{12} \)
a = \( \frac{13x}{12} \) + \( \frac{-9}{12} \)
a = 1\(\frac{1}{12}\)x - \(\frac{3}{4}\)
Simplify (y + 3)(y + 4)
| y2 - 7y + 12 | |
| y2 - y - 12 | |
| y2 + 7y + 12 | |
| y2 + y - 12 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 3)(y + 4)
(y x y) + (y x 4) + (3 x y) + (3 x 4)
y2 + 4y + 3y + 12
y2 + 7y + 12
Factor y2 - 3y - 10
| (y + 5)(y - 2) | |
| (y - 5)(y + 2) | |
| (y + 5)(y + 2) | |
| (y - 5)(y - 2) |
To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce -10 as well and sum (Inside, Outside) to equal -3. For this problem, those two numbers are -5 and 2. Then, plug these into a set of binomials using the square root of the First variable (y2):
y2 - 3y - 10
y2 + (-5 + 2)y + (-5 x 2)
(y - 5)(y + 2)
Which types of triangles will always have at least two sides of equal length?
equilateral and right |
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isosceles and right |
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equilateral, isosceles and right |
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equilateral and isosceles |
An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.
If the length of AB equals the length of BD, point B __________ this line segment.
intersects |
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midpoints |
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bisects |
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trisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.