| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.19 |
| Score | 0% | 44% |
Solve for c:
-2c - 6 = 9 - 7c
| 1\(\frac{1}{3}\) | |
| -2 | |
| 3 | |
| -3 |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-2c - 6 = 9 - 7c
-2c = 9 - 7c + 6
-2c + 7c = 9 + 6
5c = 15
c = \( \frac{15}{5} \)
c = 3
Solve 8c - 3c = c - 5x - 4 for c in terms of x.
| -2\(\frac{1}{2}\)x + 3 | |
| -\(\frac{2}{7}\)x - \(\frac{4}{7}\) | |
| -\(\frac{1}{4}\)x - \(\frac{1}{6}\) | |
| 1\(\frac{5}{9}\)x - \(\frac{7}{9}\) |
To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.
8c - 3x = c - 5x - 4
8c = c - 5x - 4 + 3x
8c - c = -5x - 4 + 3x
7c = -2x - 4
c = \( \frac{-2x - 4}{7} \)
c = \( \frac{-2x}{7} \) + \( \frac{-4}{7} \)
c = -\(\frac{2}{7}\)x - \(\frac{4}{7}\)
A cylinder with a radius (r) and a height (h) has a surface area of:
π r2h |
|
π r2h2 |
|
2(π r2) + 2π rh |
|
4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
The formula for the area of a circle is which of the following?
c = π r2 |
|
c = π d |
|
c = π d2 |
|
c = π r |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
For this diagram, the Pythagorean theorem states that b2 = ?
a2 - c2 |
|
c - a |
|
c2 + a2 |
|
c2 - a2 |
The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)