ASVAB Math Knowledge Practice Test 266487

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2a - 6a = -a + 3x - 3 for a in terms of x.

-5\(\frac{1}{2}\)x + 4\(\frac{1}{2}\)
x + \(\frac{3}{5}\)
-x - 1\(\frac{2}{5}\)
3x - 1