ASVAB Math Knowledge Practice Test 267189

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 6c - 3c = 2c - 2y - 7 for c in terms of y.

y - \(\frac{3}{14}\)
\(\frac{7}{9}\)y - \(\frac{1}{3}\)
\(\frac{1}{14}\)y - \(\frac{9}{14}\)
\(\frac{1}{4}\)y - 1\(\frac{3}{4}\)