ASVAB Math Knowledge Practice Test 267400 Results

Your Results Global Average
Questions 5 5
Correct 0 2.94
Score 0% 59%

Review

1

What is 5a2 - 2a2?

73% Answer Correctly
3a2
10a2
7
a24

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a2 - 2a2 = 3a2


2

If side a = 9, side b = 4, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{13} \)
\( \sqrt{106} \)
\( \sqrt{74} \)
\( \sqrt{97} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 92 + 42
c2 = 81 + 16
c2 = 97
c = \( \sqrt{97} \)


3

Solve for b:
b2 - 81 = 0

58% Answer Correctly
9 or -9
-2 or -9
2 or -8
-4 or -5

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

b2 - 81 = 0
(b - 9)(b + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 9) or (b + 9) must equal zero:

If (b - 9) = 0, b must equal 9
If (b + 9) = 0, b must equal -9

So the solution is that b = 9 or -9


4

If the length of AB equals the length of BD, point B __________ this line segment.

45% Answer Correctly

trisects

bisects

midpoints

intersects


Solution

A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.


5

Factor y2 - 7y + 10

54% Answer Correctly
(y + 5)(y + 2)
(y + 5)(y - 2)
(y - 5)(y - 2)
(y - 5)(y + 2)

Solution

To factor a quadratic expression, apply the FOIL method (First, Outside, Inside, Last) in reverse. First, find the two Last terms that will multiply to produce 10 as well and sum (Inside, Outside) to equal -7. For this problem, those two numbers are -5 and -2. Then, plug these into a set of binomials using the square root of the First variable (y2):

y2 - 7y + 10
y2 + (-5 - 2)y + (-5 x -2)
(y - 5)(y - 2)