ASVAB Math Knowledge Practice Test 267472 Results

Your Results Global Average
Questions 5 5
Correct 0 3.07
Score 0% 61%

Review

1

Which of the following is not true about both rectangles and squares?

64% Answer Correctly

the lengths of all sides are equal

the perimeter is the sum of the lengths of all four sides

all interior angles are right angles

the area is length x width


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

The dimensions of this trapezoid are a = 4, b = 5, c = 7, d = 6, and h = 3. What is the area?

51% Answer Correctly
19\(\frac{1}{2}\)
30
9
16\(\frac{1}{2}\)

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(5 + 6)(3)
a = ½(11)(3)
a = ½(33) = \( \frac{33}{2} \)
a = 16\(\frac{1}{2}\)


3

What is 6a3 - 8a3?

74% Answer Correctly
14
-2
-2a3
a36

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

6a3 - 8a3 = -2a3


4

If a = -6 and x = -9, what is the value of 2a(a - x)?

69% Answer Correctly
-36
252
-12
80

Solution

To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

2a(a - x)
2(-6)(-6 + 9)
2(-6)(3)
(-12)(3)
-36


5

The dimensions of this cylinder are height (h) = 8 and radius (r) = 3. What is the surface area?

48% Answer Correctly
40π
130π
66π
196π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 8)
sa = 2π(9) + 2π(24)
sa = (2 x 9)π + (2 x 24)π
sa = 18π + 48π
sa = 66π