ASVAB Math Knowledge Practice Test 267660 Results

Your Results Global Average
Questions 5 5
Correct 0 3.08
Score 0% 62%

Review

1

Solve for c:
c + 4 = \( \frac{c}{4} \)

46% Answer Correctly
-\(\frac{18}{73}\)
\(\frac{8}{13}\)
3\(\frac{3}{13}\)
-5\(\frac{1}{3}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

c + 4 = \( \frac{c}{4} \)
4 x (c + 4) = c
(4 x c) + (4 x 4) = c
4c + 16 = c
4c + 16 - c = 0
4c - c = -16
3c = -16
c = \( \frac{-16}{3} \)
c = -5\(\frac{1}{3}\)


2

A cylinder with a radius (r) and a height (h) has a surface area of:

53% Answer Correctly

4π r2

2(π r2) + 2π rh

π r2h

π r2h2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


3

Solve for b:
-5b - 5 = -1 + 6b

59% Answer Correctly
-\(\frac{4}{11}\)
-1
\(\frac{2}{3}\)
1\(\frac{1}{6}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-5b - 5 = -1 + 6b
-5b = -1 + 6b + 5
-5b - 6b = -1 + 5
-11b = 4
b = \( \frac{4}{-11} \)
b = -\(\frac{4}{11}\)


4

If side a = 1, side b = 4, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{34} \)
\( \sqrt{68} \)
\( \sqrt{26} \)
\( \sqrt{17} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 12 + 42
c2 = 1 + 16
c2 = 17
c = \( \sqrt{17} \)


5

If a = 9, b = 4, c = 1, and d = 9, what is the perimeter of this quadrilateral?

88% Answer Correctly
13
20
23
17

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 9 + 4 + 1 + 9
p = 23