When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve c + 3c = -5c + 9z + 4 for c in terms of z.
| -z + 1\(\frac{1}{6}\) | |
| z + \(\frac{2}{3}\) | |
| -z + \(\frac{1}{3}\) | |
| -\(\frac{1}{3}\)z + \(\frac{7}{9}\) |