ASVAB Math Knowledge Practice Test 268652 Results

Your Results Global Average
Questions 5 5
Correct 0 3.04
Score 0% 61%

Review

1

What is 5a - 2a?

79% Answer Correctly
3a
10a2
10a
a2

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a - 2a = 3a


2

What is the area of a circle with a radius of 3?

69% Answer Correctly
81π

Solution

The formula for area is πr2:

a = πr2
a = π(32)
a = 9π


3

If side a = 1, side b = 9, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{10} \)
\( \sqrt{58} \)
\( \sqrt{82} \)
\( \sqrt{13} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 12 + 92
c2 = 1 + 81
c2 = 82
c = \( \sqrt{82} \)


4

Solve for c:
6c + 4 > \( \frac{c}{7} \)

44% Answer Correctly
c > 1\(\frac{5}{19}\)
c > -\(\frac{28}{41}\)
c > 1\(\frac{4}{5}\)
c > 1\(\frac{27}{29}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.

6c + 4 > \( \frac{c}{7} \)
7 x (6c + 4) > c
(7 x 6c) + (7 x 4) > c
42c + 28 > c
42c + 28 - c > 0
42c - c > -28
41c > -28
c > \( \frac{-28}{41} \)
c > -\(\frac{28}{41}\)


5

Solve for z:
z2 - 8z + 14 = -z + 2

48% Answer Correctly
-4 or -8
7 or -3
1 or -6
3 or 4

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

z2 - 8z + 14 = -z + 2
z2 - 8z + 14 - 2 = -z
z2 - 8z + z + 12 = 0
z2 - 7z + 12 = 0

Next, factor the quadratic equation:

z2 - 7z + 12 = 0
(z - 3)(z - 4) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 3) or (z - 4) must equal zero:

If (z - 3) = 0, z must equal 3
If (z - 4) = 0, z must equal 4

So the solution is that z = 3 or 4