| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
What is 5a - 2a?
| 3a | |
| 10a2 | |
| 10a | |
| a2 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a - 2a = 3a
What is the area of a circle with a radius of 3?
| 4π | |
| 9π | |
| 6π | |
| 81π |
The formula for area is πr2:
a = πr2
a = π(32)
a = 9π
If side a = 1, side b = 9, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{10} \) | |
| \( \sqrt{58} \) | |
| \( \sqrt{82} \) | |
| \( \sqrt{13} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 12 + 92
c2 = 1 + 81
c2 = 82
c = \( \sqrt{82} \)
Solve for c:
6c + 4 > \( \frac{c}{7} \)
| c > 1\(\frac{5}{19}\) | |
| c > -\(\frac{28}{41}\) | |
| c > 1\(\frac{4}{5}\) | |
| c > 1\(\frac{27}{29}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6c + 4 > \( \frac{c}{7} \)
7 x (6c + 4) > c
(7 x 6c) + (7 x 4) > c
42c + 28 > c
42c + 28 - c > 0
42c - c > -28
41c > -28
c > \( \frac{-28}{41} \)
c > -\(\frac{28}{41}\)
Solve for z:
z2 - 8z + 14 = -z + 2
| -4 or -8 | |
| 7 or -3 | |
| 1 or -6 | |
| 3 or 4 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
z2 - 8z + 14 = -z + 2
z2 - 8z + 14 - 2 = -z
z2 - 8z + z + 12 = 0
z2 - 7z + 12 = 0
Next, factor the quadratic equation:
z2 - 7z + 12 = 0
(z - 3)(z - 4) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 3) or (z - 4) must equal zero:
If (z - 3) = 0, z must equal 3
If (z - 4) = 0, z must equal 4
So the solution is that z = 3 or 4