ASVAB Math Knowledge Practice Test 269137 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

If side a = 1, side b = 3, what is the length of the hypotenuse of this right triangle?

63% Answer Correctly
\( \sqrt{73} \)
\( \sqrt{5} \)
\( \sqrt{162} \)
\( \sqrt{10} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 12 + 32
c2 = 1 + 9
c2 = 10
c = \( \sqrt{10} \)


2

For this diagram, the Pythagorean theorem states that b2 = ?

47% Answer Correctly

c - a

a2 - c2

c2 + a2

c2 - a2


Solution

The Pythagorean theorem defines the relationship between the side lengths of a right triangle. The length of the hypotenuse squared (c2) is equal to the sum of the two perpendicular sides squared (a2 + b2): c2 = a2 + b2 or, solved for c, \(c = \sqrt{a + b}\)


3

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

π r2h2

2(π r2) + 2π rh

π r2h

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


4

If a = 1, b = 4, c = 6, and d = 4, what is the perimeter of this quadrilateral?

88% Answer Correctly
15
20
22
16

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 1 + 4 + 6 + 4
p = 15


5

The dimensions of this cylinder are height (h) = 4 and radius (r) = 8. What is the surface area?

48% Answer Correctly
12π
90π
192π
110π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(82) + 2π(8 x 4)
sa = 2π(64) + 2π(32)
sa = (2 x 64)π + (2 x 32)π
sa = 128π + 64π
sa = 192π