ASVAB Math Knowledge Practice Test 269227

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6c + 3c = c - 8z + 7 for c in terms of z.

1\(\frac{2}{3}\)z + \(\frac{2}{3}\)
-14z - 8
1\(\frac{4}{7}\)z - 1
-7z - 4\(\frac{1}{2}\)