ASVAB Math Knowledge Practice Test 269823 Results

Your Results Global Average
Questions 5 5
Correct 0 3.09
Score 0% 62%

Review

1

Which of the following expressions contains exactly two terms?

83% Answer Correctly

polynomial

monomial

binomial

quadratic


Solution

A monomial contains one term, a binomial contains two terms, and a polynomial contains more than two terms.


2

If side a = 3, side b = 7, what is the length of the hypotenuse of this right triangle?

64% Answer Correctly
\( \sqrt{58} \)
\( \sqrt{52} \)
\( \sqrt{80} \)
\( \sqrt{53} \)

Solution

According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:

c2 = a2 + b2
c2 = 32 + 72
c2 = 9 + 49
c2 = 58
c = \( \sqrt{58} \)


3

The endpoints of this line segment are at (-2, -3) and (2, 1). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -2\(\frac{1}{2}\)x + 1
y = \(\frac{1}{2}\)x + 1
y = -x - 2
y = x - 1

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -3) and (2, 1) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (-3.0)}{(2) - (-2)} \) = \( \frac{4}{4} \)
m = 1

Plugging these values into the slope-intercept equation:

y = x - 1


4

Solve for a:
5a - 3 < -6 - 7a

55% Answer Correctly
a < -\(\frac{2}{5}\)
a < -\(\frac{1}{4}\)
a < \(\frac{1}{5}\)
a < -\(\frac{1}{7}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

5a - 3 < -6 - 7a
5a < -6 - 7a + 3
5a + 7a < -6 + 3
12a < -3
a < \( \frac{-3}{12} \)
a < -\(\frac{1}{4}\)


5

Simplify (2a)(5ab) - (4a2)(6b).

63% Answer Correctly
34a2b
14ab2
-14a2b
34ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(2a)(5ab) - (4a2)(6b)
(2 x 5)(a x a x b) - (4 x 6)(a2 x b)
(10)(a1+1 x b) - (24)(a2b)
10a2b - 24a2b
-14a2b