When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3b + 6b = 5b - 4y - 1 for b in terms of y.
| 3y - 1\(\frac{1}{3}\) | |
| -y + \(\frac{2}{3}\) | |
| 5y + \(\frac{1}{2}\) | |
| \(\frac{13}{16}\)y - \(\frac{1}{16}\) |