ASVAB Math Knowledge Practice Test 270958

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -6c - 2c = 4c + 3z + 9 for c in terms of z.

z + 4
-\(\frac{1}{2}\)z - \(\frac{9}{10}\)
-\(\frac{8}{17}\)z + \(\frac{9}{17}\)
z + \(\frac{1}{2}\)